2x^2+8x=896

Solution for 2x^2+8x=896 equation:

2x^2+8x=896

We move all terms to the left:

2x^2+8x-(896)=0

a = 2; b = 8; c = -896;
Δ = b2-4ac
Δ = 82-4·2·(-896)
Δ = 7232
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7232}=\sqrt{64*113}=\sqrt{64}*\sqrt{113}=8\sqrt{113}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8\sqrt{113}}{2*2}=\frac{-8-8\sqrt{113}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8\sqrt{113}}{2*2}=\frac{-8+8\sqrt{113}}{4}
$